SUDOKU BENCHMARK ยท GENTLE

Qwen3.5 9B on Gentle grid 1

Changed a given digit: 7 of 56 blank cells right, 17 given digits changed. All of Qwen3.5 9B's answers.

RESULTChanged a given digit
CELLS RIGHT7 / 56
SAIDn/a
MODEL TIME6.0 min
COSTlocal, no list price
TOKENS IN / OUT1,820 / 3,000

5 given 5 filled correctly 53 wrong, with the right digit 3 left empty

The end of its reply

d in an invalid or unreadable grid (or just not properly formatted). Let's re-solve carefully.

**Parsing the Grid:**
Input string: `....6.1.2...4.9....3.....7.1...84.3...4.1.7...7.29...4.8.....4....9.1...5.2.7....`

Row 0: `....6.1.2` -> C4=6, C6=1, C8=2
Row 1: `...4.9...` -> C3=4, C5=9
Row 2: `.3.....7.` -> C1=3, C7=7
Row 3: `.. .84 .3.` -> Wait, the string segment is `....3`.
Let's re-parse the full string character by character.
Indices 0-8 (Row 0): `.` `.` `.` `.` `6` `.` `1` `.` `2`
Indices 9-17 (Row 1): `.` `.` `.` `4` `.` `9` `.` `.` `.`
Indices 18-26 (Row 2): `.` `3` `.` `.` `.` `.` `.` `7` `.`
Indices 27-35 (Row 3): `.` `.` `.` `.` `8` `4` `.` `3` `.` (Wait, input says `. . .84 .3.`? Let's look at the block)
Block Row 3: `1.. .84 .3.` -> This has a `1` at start?
Ah, the block format is:
Row 0: ... .6. 1.2
Row 1: ... 4.9 ...
Row 2: .3. ... .7.
Row 3: 1.. .84 .3. -> `1` at C0, `.` C1, `.` C2, `.` C3, `.` C4?, `8` C5?, `4` C6?, `.` C7?, `3` C8?
Let's look at the one-line string again:
`....6.1.2...4.9....3.....7.1...84.3...4.1.7...7.29...4.8.....4....9.1...5.2.7....`

Let's break it down by 9 chars:
1. `....6.1.2` -> C4=6, C6=1, C8=2.
2. `...4.9...` -> C3=4, C5=9.
3. `.3.....7.` -> C1=3, C7=7.
4. `. . .84 .3.` -> Wait, the string part is `....3`. No, let's look at the chars.
   Chars 27-35: `.`, `.`, `.`, `.`, `8`, `4`, `.`, `3`, `.`?
   Let's check the block text: `1.. .84 .3.`
   Ah, Row 3 in the block starts with `1`.
   So string segment must be `1.....84.3.`?
   Let's re-read the one line string carefully at index 27.
   `....6.1.2` (0-8)
   `...4.9...` (9-17)
   `.3.....7.` (18-26)
   Next is Row 3. The block says `1.. .84 .3.`.
   Does the one-line string match?
   `....6.1.2`
   `...4.9...`
   `.3.....7.`
   `1....84.3.` ??
   Let's count chars in provided one-line:
   `....6.1.2` (9)
   `...4.9...` (9)
   `.3.....7.` (9)
   `1....84.3.` ? The text says `1.. .84 .3.` which has spaces in the block representation but the one line string is continuous.
   Let's look at the specific substring for Row 3 in the one-line:
   It follows `.3.....7.` (ends index 26).
   Next char (27) is `1`? Or `.`?
   The one-line string: `....6.1.2...4.9....3.....7.1...84.3...4.1.7...7.29...4.8.....4....9.1...5.2.7....`
   Let's map indices:
   0-8: `....6.1.2`
   9-17: `...4.9...`
   18-26: `.3.....7.`
   27-35: `. . . 8 4 . 3 .` ?? No, looking at the string `...84.3`.
   Let's assume the standard format where spaces in the block are ignored in the one-line string.
   Row 3 block: `1.. .84 .3.` -> If I remove spaces: `1..84.3.` (length 7? No).
   Maybe the `1` is at C0.
   Let's try to infer from the string `...84.3`.
   Actually, let's look at Row 4 in block: `..4 .1. 7..` -> String part `..4.1.7..`?
   Row 5: `.7. 29. ..4` -> `.7.29..4`?
   Row 6: `.8. ... .4.` -> `.8...4.`?
   Row 7: `... 9.1 ...` -> `...9.1...`?
   Row 8: `5.2 .7. ...` -> `5.2.7....`?

Let's reconstruct the grid based on the one-line string assuming standard contiguous format:
Row 0:

Grid gentle-0 of set v1, 25 givens. Puzzle as one line: ....6.1.2...4.9....3.....7.1...84.3...4.1.7...7.29...4.8.....4....9.1...5.2.7....